Answer
$0$
Work Step by Step
$\lim\limits_{x \to \infty}e^{-x^{2}}=\lim\limits_{x \to \infty}\frac{1}{e^{-x^{2}}}$
$=\frac{1}{e^{\infty}}=\frac{1}{\infty}$
Hence, $\lim\limits_{x \to \infty}e^{-x^{2}}=0$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 6 - Inverse Functions - 6.3* The Natural Exponential Function - 6.3* Exercises - Page 452: 28
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
