Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3* The Natural Exponential Function - 6.3* Exercises - Page 452: 14


(a) $0.1565$ (b) $4.5139$

Work Step by Step

(a) $ln(\frac{x+1}{x})=2$ $(\frac{x+1}{x})=e^{2}$ $x=0.1565$ (b) $e^{1/(x-4)}=7$ $lne^{1/(x-4)}=ln7$ $\frac{1}{x-4}=1.946$ Hence, $x=4.5139$
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