Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 6 - Inverse Functions - 6.3 Logarithmic Functions - 6.3 Exercises - Page 426: 19


(a) 1.430677 (b) 3.680144 (c) 1.651496

Work Step by Step

Since, change of base formula defines $\log_{a}x=\frac{logx}{loga}$ Therefore, (a) $\log_{5}10=\frac{log10}{log5}$ Hence, $\log_{5}10=\frac{log10}{log5}=1.430677$ (b) $\log_{3}57=\frac{log57}{log3}$ Hence, $\log_{3}57=\frac{log57}{log3}=3.680144$ (c) $\log_{2}\pi=\frac{log\pi}{log2}$ Hence, $\log_{2}\pi=\frac{log\pi}{log2}$ =1.651496
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