Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 5 - Applications of Integration - 5.5 Average Value of a Function - 5.5 Exercises - Page 391: 21


$$ 0.4\rm L$$

Work Step by Step

$$V_{ave} = \frac{1}{5} \int^5_0 V(t) dt = \frac{1}{4\pi} \int^5_{0} [1-cos(\frac{2}{5} \pi t)] dt $$ $$=\frac{1}{4\pi} [t - \frac{5}{2\pi} sin (\frac{2}{5} \pi t)]^5_0 = \frac{5}{4\pi} \approx 0.4\rm L$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.