Answer
$$6kg/m $$
Work Step by Step
$$\rho_{ave} = \frac{1}{8} \int^8_0 \frac{12}{\sqrt{x+1}} dx = \frac{3}{2} \int^8_0 (1+x)^{-1/2} dx = [3\sqrt{x+1}] ^8_0 = 6kg/m $$
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