Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 5 - Applications of Integration - 5.5 Average Value of a Function - 5.5 Exercises - Page 391: 19

Answer

$$6kg/m $$

Work Step by Step

$$\rho_{ave} = \frac{1}{8} \int^8_0 \frac{12}{\sqrt{x+1}} dx = \frac{3}{2} \int^8_0 (1+x)^{-1/2} dx = [3\sqrt{x+1}] ^8_0 = 6kg/m $$
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