Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.5 The Substitution Rule - 4.5 Exercises - Page 347: 71


$$\int e^x\sqrt{1+e^x}dx=\frac{2}{3}(1+e^x)^{3/2}+c$$

Work Step by Step

To evaluate the integral $$\int e^x\sqrt{1+e^x}dx$$ we will use substitution $e^x=t$ which gives us $e^xdx=dt$. Putting this into the integral we get: $$\int \sqrt{1+e^x}e^xdx=\int\sqrt tdt=\int t^{1/2}dt=\frac{t^{3/2}}{\frac{3}{2}}+c=\frac{2}{3}t^{3/2}+c$$ where $c$ is arbitrary constant. Now we have to express solution in terms of $x$: $$\int e^x\sqrt{1+e^x}dx=\frac{2}{3}t^{3/2}+c=\frac{2}{3}(1+e^x)^{3/2}+c$$
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