Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.5 The Substitution Rule - 4.5 Exercises - Page 347: 60



Work Step by Step

To find the integral $$\int_0^3xf(x^2)dx$$ we will use substitution $x^2=t$ which gives us $2xdx=dt\Rightarrow xdx=\frac{dt}{2}$ and the integration bounds would be: for $x=0$ we have $t=0$ and for $x=3$ we have $t=9$. Putting all this into the integral we get: $$\int_0^3f(x^2)xdx=\int_0^9f(t)\frac{dt}{2}=\frac{1}{2}\int_0^9f(t)dt$$ Based on the preposition that $$\int_0^9f(x)dx=4$$ (doesn't metter how we name the integration variable), we now have: $$\int_0^3xf(x^2)dx=\frac{1}{2}\int_0^9f(t)dt=\frac{1}{2}\cdot 4=2$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.