Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.3 The Fundamental Theorem of Calculus - 4.3 Exercises - Page 327: 8


$g'(x) = cos(x^2)$

Work Step by Step

We are told to find the derivative using Part 1 of the Fundamental Theorem of Calculus given the expression: $g(x) = \int ^{x}_{1}cos(t^2)dt$ Since $g(x) = \int^{b}_{a}f(t)dt$ $g'(x) = f(x)$ Thus, $g'(x) = cos(x^2)$
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