Answer
$10\pi$
Work Step by Step
Evaluate the integral: $\int^{5}_{-5}\pi dx$
Recall the 2nd part of the Fundamental Theorem of Calculus:
$∫^b_af(x)dx=F(b)−F(a)$
Find $F(x)$:
$F(x)=\int\pi dx$
$F(x)=\pi \int1dx$
$F(x)=\pi x$
(since $\pi$ is a constant it can be pulled out of the integral)
Now evaluate $F(b)−F(a)$:
$F(5)−F(-5)$
$5\pi- -5\pi$
$10\pi$