Answer
$$
\int_{0}^{9}[2 f(x)+3 g(x)] d x=122
$$
Work Step by Step
$$
\begin{aligned}
\int_{0}^{9}[2 f(x)+3 g(x)] d x&=2 \int_{0}^{9} f(x) d x+3 \int_{0}^{9} g(x) d x \\
& \,\,\,\,\,\,\,\,\,\ \text{ Use values of integrals }\\
& \,\,\,\,\,\,\,\,\,\ [ \int_{0}^{9} f(x) d x=37 \text { and } \int_{0}^{9} g(x) d x=16 ] \\
&=2(37)+3(16) \\
&=122
\end{aligned}
$$