Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.2 The Definite Integral - 4.2 Exercises - Page 318: 49

Answer

$$ \int_{0}^{9}[2 f(x)+3 g(x)] d x=122 $$

Work Step by Step

$$ \begin{aligned} \int_{0}^{9}[2 f(x)+3 g(x)] d x&=2 \int_{0}^{9} f(x) d x+3 \int_{0}^{9} g(x) d x \\ & \,\,\,\,\,\,\,\,\,\ \text{ Use values of integrals }\\ & \,\,\,\,\,\,\,\,\,\ [ \int_{0}^{9} f(x) d x=37 \text { and } \int_{0}^{9} g(x) d x=16 ] \\ &=2(37)+3(16) \\ &=122 \end{aligned} $$
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