Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 4 - Integrals - 4.2 The Definite Integral - 4.2 Exercises - Page 318: 47

Answer

$\int_{-1}^{5}f(x)dx$

Work Step by Step

$$\begin{align*} &\int_{-2}^{2}f(x)dx+\int_{2}^{5}f(x)dx-\int_{-2}^{-1}f(x)dx\\ &=\left(\int_{-2}^{2}f(x)dx+\int_{2}^{5}f(x)dx\right)-\int_{-2}^{-1}f(x)dx\\ &=\int_{-2}^{5}f(x)dx-\int_{-2}^{-1}f(x)dx\\ &=\int_{-2}^{5}f(x)dx+\int_{-1}^{-2}f(x)dx\\ &=\int_{-1}^{-2}f(x)dx+\int_{-2}^{5}f(x)dx\\ &=\int_{-1}^{5}f(x)dx \end{align*}$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.