Answer
$\int_{-1}^{5}f(x)dx$
Work Step by Step
$$\begin{align*}
&\int_{-2}^{2}f(x)dx+\int_{2}^{5}f(x)dx-\int_{-2}^{-1}f(x)dx\\
&=\left(\int_{-2}^{2}f(x)dx+\int_{2}^{5}f(x)dx\right)-\int_{-2}^{-1}f(x)dx\\
&=\int_{-2}^{5}f(x)dx-\int_{-2}^{-1}f(x)dx\\
&=\int_{-2}^{5}f(x)dx+\int_{-1}^{-2}f(x)dx\\
&=\int_{-1}^{-2}f(x)dx+\int_{-2}^{5}f(x)dx\\
&=\int_{-1}^{5}f(x)dx
\end{align*}$$