## Calculus 8th Edition

By use the graph of $f(x) = sinx, -\frac{\pi}{2} \lt x \leq \frac{\pi}{2}$ to find the absolute and local maximum and minimum values of f. The sketch of the graph of f'in the interval $[-\frac{\pi}{2}, \frac{\pi}{2}]$ is shown below:
From the graph, observe that the absolute minimum of f is, $f(-\frac{\pi }{2})= -1$ And the absolute maximum of f is, $f(\frac{\pi }{2})= 1$