Answer
No absolute or local maximum.
Absolute minimum = $0$
No local minimum.
Work Step by Step
No absolute or local maximum.
$f(0)$ = $\sin 0$ = $0$
Absolute minimum = $0$
No local minimum.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 3 - Applications of Differentiation - 3.1 Maximum and Minimum Values - 3.1 Execises - Page 211: 19
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
