Answer
(a) The derivative of
$$
y=\tan x
$$
is
$$
d y=\sec ^{2} x d x
$$
(b) When $$ x=\pi / 4 \,\,\,\ \text{and} \,\,\,\,\, d x=-0.1$$,
$$
dy=[\sec (\pi / 4)]^{2}(-0.1)=(\sqrt{2})^{2}(-0.1)=-0.2$$
Work Step by Step
(a) The derivative of
$$
y=\tan x
$$
is
$$
d y=\sec ^{2} x d x
$$
(b) When $$ x=\pi / 4 \,\,\,\ \text{and} \,\,\,\,\, d x=-0.1$$,
$$
dy=[\sec (\pi / 4)]^{2}(-0.1)=(\sqrt{2})^{2}(-0.1)=-0.2$$