## Calculus 8th Edition

$y-1 = -1/8*(x-3)$
The derivative of the function should give us the slope. $$f'(x) = -(x^2-5)^{-3/2}, f'(3) = -4^{-1.5} = -1/8$$ We also find a point it goes through by plugging in $a=3$to f(x) instead of f'(x) $$f(3) = 1$$ In point slope form, $y-1 = -1/8*(x-3)$