## Calculus 8th Edition

$$y - 2 = 1/4(x-4)$$
To find the linearization we first need to calculate the slope by taking the derivative. $$f'(x) = 1/2* (x^{-1/2})$$ $$f'(4) = 1/2* (4^{-1/2})=1/2*2^{-1}= 1/4$$ Then we need to find the point where the line passes through, $$f(4) = 2$$ Using the point-slope form, $$y - 2 = 1/4(x-4)$$