Answer
$(2t - c)sin(t) + t^2cos(t)$
Work Step by Step
$y= ccos(t)+ t^2sin(t)$
$y'= -csin(t) + (2tsin(t) + t^2cos(t))$
$y' = 2tsin(t) - csin(t) + t^2cos(t)$
$y'= (2t -c)sin(t) + t^2cos(t)$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 2 - Derivatives - 2.4 Derivatives of Trigonometric Functions - 2.4 Exercises - Page 150: 7
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