Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.4 Derivatives of Trigonometric Functions - 2.4 Exercises - Page 150: 5

Answer

$=sec^{2}(\theta)tan(\theta)+sec^{3}(\theta)$

Work Step by Step

Use the product rule: $(f(x)g(x))'=f'(x)g(x)+f(x)g'(x))$ $(sec(\theta)tan(\theta)=(sec(\theta))'tan(\theta)+sec(\theta)(tan(\theta))'=sec^{2}(\theta)tan(\theta)+sec^{3}(\theta)$
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