## Calculus 8th Edition

$1.5x^{.5}$
Chain Rule: $f(x)=x^{n}$ $f'(x)=(n)x^{n-1}$ And so, $f(x)=x^{1.5}$ $f'(x)=(1.5)x^{1.5-1}=(1.5)x^{.5}=1.5x^{.5}$