## Calculus 8th Edition

$g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$ Domain: t $\gt$ 0
$g(t) = \frac{1}{\sqrt t} = t^{-1/2}$ $g'(t) = (-1/2)t^{(-1/2) - 1}$ $g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$ The domain is t $\gt$ 0 because for any negative t value or if t = 0, then g'(t) would be undefined