Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 2 - Derivatives - 2.2 The Derivative as a Function - 2.2 Exercises: 24


$g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$ Domain: t $\gt$ 0

Work Step by Step

$g(t) = \frac{1}{\sqrt t} = t^{-1/2}$ $g'(t) = (-1/2)t^{(-1/2) - 1}$ $g'(t) = \frac{-1}{2}t^{\frac{-3}{2}}$ The domain is t $\gt$ 0 because for any negative t value or if t = 0, then g'(t) would be undefined
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