Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 16 - Vector Calculus - 16.2 Line Integrals - 16.2 Exercises - Page 1126: 45


$\approx 1.67 \times 10^{4} ft-lb$

Work Step by Step

The magnitude of gravitational force acting on the man $+$ Can of paint $=160+25=185lbs$ When we are moving in the upward direction, then we have $F \cdot dr=185 dr$ $W=\int_C F\cdot dr=185 \int_C dr$ Here, $C$ shows a vertical line segment joining the lower and upper part of the silo, then we have $W=\int_C F\cdot dr=185 \int_C dr=185(90)$ or, $W=16, 650 ft-lbs \approx 1.67 \times 10^{4} ft-lb$
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