## Calculus 8th Edition

$\dfrac{7}{3}+\dfrac{e^2-e}{2}$
$W=\int_C F\cdot dr=\int_0^{1} (y^2+1)^2(2y dy)+y[e^{y^2+1}] dy$ or, $=\int_0^{1} 2y \times (y^2+1)^2+y \times [e^{y^2+1}] dy$ Suppose, $y^2+1=t; 2y dy =dt$ $=\int_1^2 t^2+\dfrac{e^t}{2} dt$ $=[\dfrac{t^3}{3}+\dfrac{e^t}{2}]_1^{2}$ $=[\dfrac{2^3}{3}+\dfrac{e^2}{2}]-[\dfrac{1^3}{3}+\dfrac{e^1}{2}]$ $=\dfrac{7}{3}+\dfrac{e^2-e}{2}$