Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - Review - Exercises - Page 1024: 48


$\sqrt 5,\lt 2,0,1 \gt$

Work Step by Step

Our aim is to determine the maximum rate of change of $f(x,y)$.In order to find this, we have : $D_uf=|\nabla f(x,y,z)|$ Formula to calculate the directional derivative: $D_uf=\nabla f(x,y,z) \cdot u$ Given: $f(x,y,z)=ze^{xy}$ $\nabla f(x,y,z)=\lt zye^{xy},zxe^{xy},e^{xy} \gt$ From the given data, we have $f(x,y,z)=f(0,1,2)$ $\nabla f(0,1,2)=\lt zye^{xy},zxe^{xy},e^{xy} \gt=\lt 2,0,1 \gt$ $|\nabla f(0,1,2)|=\sqrt{2^2+0^2+(1)^2}=\sqrt 5$ Therefore, the maximum rate of change of $f(x,y)$ and the direction is: $\sqrt 5,\lt 2,0,1 \gt$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.