Answer
$$\approx-0.017^\circ/km$$
Work Step by Step
Our aim is to determine the rate of change of temperature in the direction.
From the graph given in the question, we have:
Rate of change $$=\dfrac{24-30}{350} \approx-0.017^\circ/km$$
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 14 - Partial Derivatives - 14.6 Directional Derivatives and the Gradient Vector - 14.6 Exercises - Page 996: 2
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