#### Answer

$$f_x = 2xy - 0 = 2xy$$
$$f_y = x^2 - 12xy$$

#### Work Step by Step

To find $f_x$, we treat $y$ as a constant and differentiate with respect to $x$. Thus
$$f_x = 2xy - 0 = 2xy.$$
Similarly, to find $f_y$, we treat $x$ s a constant and differentiate with respect to $y$. Thus
$$f_y = x^2 - 12xy.$$