Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 14 - Partial Derivatives - 14.3 Partial Derivatives - 14.3 Exercises - Page 964: 15

Answer

$$f_x = 2xy - 0 = 2xy$$ $$f_y = x^2 - 12xy$$

Work Step by Step

To find $f_x$, we treat $y$ as a constant and differentiate with respect to $x$. Thus $$f_x = 2xy - 0 = 2xy.$$ Similarly, to find $f_y$, we treat $x$ s a constant and differentiate with respect to $y$. Thus $$f_y = x^2 - 12xy.$$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.