#### Answer

$D=$ {$(x,y) | x-y \gt -1$}

#### Work Step by Step

As we are given that $G(x,y)=ln(1+x-y)$
The function $G(x,y)=ln(1+x-y)$ represents a logarithmic function which cannot be less than $0$ and exists only for positive numbers.
Thus,
$ 1+x-y \gt 0$
or, $x-y \gt -1$
or, $x-y \gt -1$
This means that $x \gt y-1$
Hence, Domain: $D=$ {$(x,y) | x-y \gt -1$}