Answer
${(x,y)| {1+x-y}\geq 0}$
Work Step by Step
Given: $f(x,y)=cos\sqrt {1+x-y}$
The given function is defined for all values of x and y except at $\sqrt {1+x-y}\geq 0$
Since, $cos(x,y)$ is continuous at $R^{2}$ and square root of the function does not exist at $R$ when it contains non-negative value.
Square both sides to obtain inequality to represent the domain.
$ {1+x-y}\geq 0$
Hence, the function $f(x,y)=cos\sqrt {1+x-y}$ is continuous on ${(x,y)| {1+x-y}\geq 0}$.
