#### Answer

The domain is given by
$$\mathcal{D}=\{(x,y)|y\geq x^2,x\neq\pm1\},$$
and it is presented on the graph below (red lines are excluded from it)

#### Work Step by Step

Here, we have two constraints:
1.The argument of the square root has to be nonnegative i.e.
$$y-x^2\geq0\Rightarrow y\geq x^2.$$
2. The denominator must not be zero i.e.
$$1-x^2\neq0\Rightarrow x\neq\pm1.$$
This means that the domain is the region including and above the parabola $y=x^2$ with the vertical lines $x=\pm1$ excluded from is.
So we write for the domain
$$\mathcal{D}=\{(x,y)|y\geq x^2,x\neq\pm1\},$$
and it is presented in the figure below (red lines are excluded from it)