## Calculus 8th Edition

$\approx 4.5 cm/s^2$, $\approx 9.0 cm/s^2$
As we are given thet the magnitude of the acceleration is $10cm/s^2$. We can see from the given figure that $\theta= 63.5^\circ$ Need to solve the tangential acceleration and normal acceleration components. 1) Tangential component of $a$ : $a_T=10 \cos \theta =10 \cos (63.5^\circ)\approx 4.5 cm/s^2$ 2) Normal component of $a$ : $a_N=10 \sin \theta$ or, $=10 \sin (63.5^\circ)$ or, $\approx 9.0 cm/s^2$