Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 13 - Vector Functions - 13.4 Motion in Space: Velocity and Acceleration - 13.4 Exercises - Page 919: 43


$\approx 4.5 cm/s^2$, $\approx 9.0 cm/s^2$

Work Step by Step

As we are given thet the magnitude of the acceleration is $10cm/s^2$. We can see from the given figure that $\theta= 63.5^\circ$ Need to solve the tangential acceleration and normal acceleration components. 1) Tangential component of $a$ : $a_T=10 \cos \theta =10 \cos (63.5^\circ)\approx 4.5 cm/s^2$ 2) Normal component of $a$ : $a_N=10 \sin \theta $ or, $=10 \sin (63.5^\circ)$ or, $ \approx 9.0 cm/s^2$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.