Answer
$\approx 4.5 cm/s^2$, $\approx 9.0 cm/s^2$
Work Step by Step
As we are given thet the magnitude of the acceleration is $10cm/s^2$.
We can see from the given figure that $\theta= 63.5^\circ$
Need to solve the tangential acceleration and normal acceleration components.
1) Tangential component of $a$ : $a_T=10 \cos \theta =10 \cos (63.5^\circ)\approx 4.5 cm/s^2$
2) Normal component of $a$ : $a_N=10 \sin \theta $
or, $=10 \sin (63.5^\circ)$
or, $ \approx 9.0 cm/s^2$
