Answer
$t>0, t\ne2$
Work Step by Step
Cosine is always defined, $\ln$ when it's argument is above zero so $t>0$, and $\frac{1}{t-2}$ is defined when $t\ne2$ so the answer is $t>0, t\ne2$.
Calculus 8th Edition
by Stewart, James
Published by
Cengage
ISBN 10:
1285740629
ISBN 13:
978-1-28574-062-1
Chapter 13 - Vector Functions - 13.1 Vector Functions and Space Curves - 13.1 Exercises - Page 893: 2
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