## Calculus 8th Edition

$\approx 1299038 J$
Horizontal component of the force is: $F=1500 cos 30 ^\circ$ $F=1500 cos 30 ^\circ=1500 \times \frac{\sqrt 3}{2}=750 \sqrt 3 N$ $d =1 km =1000 m$ As we know the work done is calculated as: $W= F.d$ Thus, $W=( 750 \sqrt 3 N) (1000 m)$ $W= 750000\sqrt 3 Nm$ $W \approx 1299038 J$