## Calculus 8th Edition

$\lt -0.39282 , 0.919615\gt and \lt 0.99282,-0.119615 \gt$
Two unit vectors that make an angle of $60^\circ$ with $v= \lt 3,4 \gt$ $x^2+y^2=1$ $x^2+((1/8)(5-6x))^2=1$ $100x^2-60x-39=0$ $x= \dfrac{3 \pm 4 \sqrt 3}{10} \approx -0.39282,0.99282$ and $y=(1/8)(5-6x)\approx (1/8)(5-6(-0.39282))\approx 0.919615$ $y=(1/8)(5-6x)\approx (1/8)(5-6(0.99282))\approx -0.119615$ Hence, the two unit vectors are: $\lt -0.39282 , 0.919615\gt and \lt 0.99282,-0.119615 \gt$