Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 11 - Infinite Sequences and Series - 11.10 Taylor and Maclaurin Series - 11.10 Exercises - Page 812: 76



Work Step by Step

Given: $\Sigma_{n=0}^{\infty}\dfrac{3^{n}}{5^{n}(n!)}$ which can be written as $\Sigma_{n=0}^{\infty}\dfrac{(3/5)^{n}}{n!}$ As we know $e^{x}=\Sigma_{n=0}^{\infty}\dfrac{x^{n}}{(n!)}$ Then, $e^{3/5}=\Sigma_{n=0}^{\infty}\dfrac{3^{n}}{5^{n}(n!)}$
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