Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Chapter 10 - Parametric Equations and Polar Coordinates - Review - Exercises - Page 730: 31



Work Step by Step

Given: $r^2=9 cos 5 \theta$ $Area,A=\int_{- \pi/10}^{\pi/10}\frac{r^2}{2}d\theta$ $=\int_{- \pi/10}^{\pi/10}\dfrac{9cos5 \theta}{2}d\theta$ $=10[\dfrac{9sin5 \theta}{10}]_{- \pi/10}^{\pi/10}$ $=18$
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