## Calculus 8th Edition

$\frac{1}{2}$
Plug in the given values into the function. From the table of values, we can see that as x goes to 0 from both the left and right hand side, y goes to $\frac{1}{2}$. Therefore, $\lim\limits_{x \to 0}$$\frac{sinx}{x+tanx}$=$\frac{1}{2}$.