Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix G - Complex Numbers - G Exercises: 19



Work Step by Step

We solve for $x$: $4x^{2}+9=0$ $4x^{2}=-9$ $x^{2}=-\displaystyle \frac{9}{4} $ $x=\displaystyle \pm\sqrt{-\frac{9}{4}}$ $=\displaystyle \pm\sqrt{-1*\frac{9}{4}}$ We use the fact that $\sqrt{-1}=i$: $=\pm\sqrt{\frac{9}{4}}i$ $=\pm\frac{3}{2}i$
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