Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix D - Trigonometry - D Exercises: 46

Answer

$(sinx+cosx)^{2}=1+sin2x$

Work Step by Step

Need to prove the identity $(sinx+cosx)^{2}=1+sin2x$ In order to prove this, take left side isolate. $(sinx+cosx)^{2}=sin^{2}x+cos^{2}x+2sinx cosx$ Since, $2sinx cosx= sin2x$, and $sin^{2}x+cos^{2}x=1$ Hence, $(sinx+cosx)^{2}=1+sin2x$
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