Calculus 8th Edition

Published by Cengage
ISBN 10: 1285740629
ISBN 13: 978-1-28574-062-1

Appendix D - Trigonometry - D Exercises - Page A32: 42


$ cos(\frac{\pi}{2}-x)=sinx$

Work Step by Step

Need to prove $ cos(\frac{\pi}{2}-x)=sinx$ Since, $ cos(A-B)=cos A cos B+sinA sin B$ Thus, $ cos(\frac{\pi}{2}-x)=cos \frac{\pi}{2} cos x+sin\frac{\pi}{2} sin x$ $ cos(\frac{\pi}{2}-x)=0.cos x+1.sin x$ Hence, $ cos(\frac{\pi}{2}-x)=sinx$
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