## Calculus 8th Edition

$y = \frac34x +6$
We are told to find the equation of the line that satisfies the following conditions: The $x$-intercept is $-8$ and the $y$-intecept is $6$ To find the equation of the line we must find the slope: $m = \frac{y_2 -y_1}{x_2 - x_1}$ and then use point slope form: $y−y_1=m(x−x_1)$ It may not be obvious at first, but the intercepts given are actually the points: $(-8,0)$ and $(0,6)$ $m =\frac{6-0}{0-(-8)} = \frac{6}{8} = \frac34$ $y - 6=\frac34x$ $y= \frac34x +6$ or $y = mx + b$ $m = \frac34$ $b = 6$ $y = \frac34x +6$