## Calculus 8th Edition

$y = x -1$
We are told to find the equation of the line that satisfies the following conditions: Passes through the points $(-1,-2), (4,3)$ To find the equation of the line we must find the slope: $m = \frac{y_2 -y_1}{x_2 - x_1}$ and then use point slope form: $y−y_1=m(x−x_1)$ $m =\frac{3-(-2)}{4-(-1)} = \frac{5}{5} = 1$ $y− 3=1(x− 4)$ $y=x -4 + 3$ $y = x -1$