Answer
a) $\ln|\frac{R-3}{R-2}|-\ln{\frac{1}{2}}$
b) $\ln2$
Work Step by Step
a)
$\int_4^R{\frac{dx}{(x-2)(x-3)}}dx$ = $\ln|\frac{R-3}{R-2}|-\ln{\frac{1}{2}}$
b)
$\int_4^R{\frac{dx}{(x-2)(x-3)}}dx$ = $\ln|\frac{R-3}{R-2}|-\ln{\frac{1}{2}}$ = $\ln2$
