Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.6 Strategies for Integration - Preliminary Questions - Page 431: 10

Answer

$$\frac{1}{2} \sec (4x) \tan (4x)+\frac{1}{2} \ln |\sec (4x)+\tan (4x)|+C$$

Work Step by Step

Since $$\int \sec ^{3} u d u=\frac{1}{2} \sec u \tan u+\frac{1}{2} \ln |\sec u+\tan u|+C$$ Then \begin{align*} \int \sec ^{3}(4 x) d x&=\frac{1}{2} \sec (4x) \tan (4x)+\frac{1}{2} \ln |\sec (4x)+\tan (4x)|+C \end{align*}
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