Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 8 - Techniques of Integration - 8.6 Strategies for Integration - Exercises - Page 431: 13


$$\frac{1}{2}\left( x+\frac{1}{8}\sin 8x\right)+C$$

Work Step by Step

Given $$\int \cos ^{2} 4 x d x$$ Then \begin{align*} \int \cos ^{2} 4 x d x&=\frac{1}{2}\int [1+\cos 8 x] d x\\ &=\frac{1}{2}\left( x+\frac{1}{8}\sin 8x\right)+C \end{align*}
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