Answer
$$\int x^n e^x dx = x^n e^x -n\int x^{n-1} e^xdx $$
Work Step by Step
Given $$\int x^n e^x dx$$
Let
\begin{align*}
u&=x^n \ \ \ \ \ \ \ \ dv= e^xdx\\
du&= nx^{n-1}\ \ \ \ \ v=e^x
\end{align*}
Then
\begin{align*}
\int x^n e^x dx&= x^n e^x -n\int x^{n-1} e^xdx
\end{align*}