Answer
$$ h'(y)= \tanh(4y)+4y\, sech^2(4y) .$$
Work Step by Step
Since $ h(y)=y\tanh(4y)$, then the derivative, by using the product rule, is given by
$$ h'(y)=\tanh(4y)+y\, sech^2(4y) (4y)'=\tanh(4y)+4y\, sech^2(4y) .$$
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 386: 40
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