Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 386: 40

Answer

$$ h'(y)= \tanh(4y)+4y\, sech^2(4y) .$$

Work Step by Step

Since $ h(y)=y\tanh(4y)$, then the derivative, by using the product rule, is given by $$ h'(y)=\tanh(4y)+y\, sech^2(4y) (4y)'=\tanh(4y)+4y\, sech^2(4y) .$$
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