Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - Chapter Review Exercises - Page 386: 11

Answer

$$\frac{e}{2}.$$

Work Step by Step

By differentiation, we have $$f'(g(x))g'(x)=2xe^{x^2}$$ hence we have $$f'(g(1))g'(1)=f'(2) 4=2e \Longrightarrow f'(2)=\frac{e}{2}.$$
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