Answer
$x=4u$.
Work Step by Step
If we assume that $x=4u$, then we have
$$\sqrt{16+x^2}=\sqrt{16+16u^2}=4\sqrt{1+u^2}.$$
Hence, the relation between $x$ and $u$ is $x=4u$.
Calculus (3rd Edition)
by Rogawski, Jon; Adams, Colin
Published by
W. H. Freeman
ISBN 10:
1464125260
ISBN 13:
978-1-46412-526-3
Chapter 7 - Exponential Functions - 7.8 Inverse Trigonometric Functions - Preliminary Questions - Page 374: 5
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