Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.1 Derivative of f(x)=bx and the Number e - Exercises - Page 328: 74


$ \frac{1}{4}(e^{9}-e^5 )$

Work Step by Step

We have $$ \int_2^3 e^{4t-3} dt= \frac{1}{4}\int_0^34e^{4t-3} dt = \frac{1}{4}\left[e^{4t-3}\right]_2^3= \frac{1}{4}(e^{9}-e^5 ) . $$
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