Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 7 - Exponential Functions - 7.1 Derivative of f(x)=bx and the Number e - Exercises - Page 328: 71



Work Step by Step

We have $$ \int_0^1\left(e^{-3x}\right) d x=\frac{1}{-3}\int_0^1 -3e^{-3x} d x =\frac{-1}{3}\left[e^{-3x}\right]_0^1= -\frac{1}{3}(e^{-3}-1) . $$
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