## Calculus (3rd Edition)

$=2.24 \mathrm{~J}.$
The work is given by the integral of force through the distance: $$\int_{-0.05}^{-0.09} 800 x d x=\left.400 x^{2}\right|_{-0.05}^{-0.09}=2.24 \mathrm{~J}.$$