Calculus (3rd Edition)

Published by W. H. Freeman
ISBN 10: 1464125260
ISBN 13: 978-1-46412-526-3

Chapter 6 - Applications of the Integral - 6.5 Work and Energy - Exercises - Page 316: 6

Answer

$=2.24 \mathrm{~J}.$

Work Step by Step

The work is given by the integral of force through the distance: $$ \int_{-0.05}^{-0.09} 800 x d x=\left.400 x^{2}\right|_{-0.05}^{-0.09}=2.24 \mathrm{~J}. $$
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